(2k+3)(2k^2-4k-3)=0

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Solution for (2k+3)(2k^2-4k-3)=0 equation: 


Simplifying
(2k + 3)(2k2 + -4k + -3) = 0

Reorder the terms:
(3 + 2k)(2k2 + -4k + -3) = 0

Reorder the terms:
(3 + 2k)(-3 + -4k + 2k2) = 0

Multiply (3 + 2k) * (-3 + -4k + 2k2)
(3(-3 + -4k + 2k2) + 2k * (-3 + -4k + 2k2)) = 0
((-3 * 3 + -4k * 3 + 2k2 * 3) + 2k * (-3 + -4k + 2k2)) = 0
((-9 + -12k + 6k2) + 2k * (-3 + -4k + 2k2)) = 0
(-9 + -12k + 6k2 + (-3 * 2k + -4k * 2k + 2k2 * 2k)) = 0
(-9 + -12k + 6k2 + (-6k + -8k2 + 4k3)) = 0

Reorder the terms:
(-9 + -12k + -6k + 6k2 + -8k2 + 4k3) = 0

Combine like terms: -12k + -6k = -18k
(-9 + -18k + 6k2 + -8k2 + 4k3) = 0

Combine like terms: 6k2 + -8k2 = -2k2
(-9 + -18k + -2k2 + 4k3) = 0

Solving
-9 + -18k + -2k2 + 4k3 = 0

Solving for variable 'k'.

The solution to this equation could not be determined.

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